1)
For a binomial distribution,
P(X=x) = nCx px (1-p)n-x
p = 0.2
n = 9
a)
P(X=5) = 9C5 0.25 (1-0.2)9-5 = 0.0165 or 1.65%
b)
P(X=0) = 9C0 0.20 (1-0.2)9-0 = 0.1342 or 13.42%
c)
P(X<3) = P(X=0) + P(X=1) + P(X=2) = 0.7382 or 73.82%
2)
For a binomial distribution,
P(X=x) = nCx px (1-p)n-x
p = 0.4
n = 5
a)
P(X=5) = 5C5 0.45 (1-0.4)5-5 = 0.0102 or 1.02%
b)
P(X>=3) = P(X=3) + P(X=4) + P(X=5) = 0.3174 or 31.74%
c)
P(X<=2) = 1-P(X>=3) =1- 0.3174 = 0.6828 or 68.28%
3)
For a binomial distribution,
P(X=x) = nCx px (1-p)n-x
p = 0.1
n = 12
a)
P(X<=2) = P(X=0) + P(X=1) + P(X=2) = 0.8891 or 88.91%
b)
P(X=0) = 12C0 0.10 (1-0.1)12-0 = 0.2824 or 28.24%
5)
For a binomial distribution,
P(X=x) = nCx px (1-p)n-x
p = 0.3
n = 11
a)
P(X=8) = 11C8 0.38 (1-0.3)11-8 = 0.0037 or 0.37%
b)
We will calculate the probability for each value of X.
x |
P(x) |
x*P |
0 |
0.019773 |
0 |
1 |
0.093217 |
0.093217 |
2 |
0.19975 |
0.399501 |
3 |
0.256822 |
0.770466 |
4 |
0.220133 |
0.880532 |
5 |
0.13208 |
0.660399 |
6 |
0.056606 |
0.339634 |
7 |
0.017328 |
0.121298 |
8 |
0.003713 |
0.029706 |
9 |
0.00053 |
0.004774 |
10 |
4.55E-05 |
0.000455 |
11 |
1.77E-06 |
1.95E-05 |
Total |
3.3 |
Expected Value = Mean = ∑px = 3.3
PS: We are only allowed to answer 4 parts per question
BINOMİAL PROBABnrTY ) The college bealth center did a survey Md fond thnt 20% of students...
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