Here population standard deviation is not given and we use sample standard deviation(s) instead of population standard deviation ( ). Also sample size is not sufficiently large( >= 30) so we need to assume that the sample comes from normal population. Then we can used one sample t confidence interval for population mean( )
Using minitab:
Step 1) Click on Stat>>>Basic Statistics >>1 sample t...
Select summarized data
Sample size: 16
Mean: 16.73
Standard deviation: 8.44
Step 2) Click on Option
Confidence level = 99
Alternative: Not equal
Then click on OK
Again Click on OK
Then we get the following output
Therefore, 99% confidence interval is from 10.51 mg/L to 22.95 mg/L
8.3.130 ofonprie coton (mou colected from organic sol Construct a 90% oorddence 16.51 14.90 15 35...
The following data represent the concentration of organic carbon (mg/L) collected from organic soil. Construct a 99% confidence interval for the mean concentration of dissolved organic carbon collected from organic soil. (Note: x overbarxequals=16.67mg/L and sequals=8.12mg/L 10.30 8.81 30.91 19.80 29.80 5.30 14.86 14.86 27.10 20.46 10.30 8.09 16.51 14.90 15.35 10.30 14.00 33.67 9.72 18.30 Construct a 99% confidence interval for the mean concentration of dissolved organic carbon collected from organic soil. (_ , _) (Use ascending order. Round...
19 of 20 (16 complete) Score: 0 of 1 pt 8.3.130 The following data represent the concentration of organic carbon (mg/L) collected from organic sol. Construct a 99 % confidence interval for the mean concentration of dissolved organic carbon collected from organic soil. (Note: x 18.58 mg/L and s 7.2 mgL) Click here to vew page 1 of the table of ontical values for the t distrbution Click here to vew page 2 of the table of critical values for...
The following data represent the concentration of dissolved organic carbon (m/L) collected from 20 samples of organic soil Assume that the population is normaly distributed. Complete parts (a) through (c) on the right 5.20 8.81 30.91 9.80 29.80 17.50 4.86 14.86 27.10 20.46 20.46 8.09 16.51 14.90 15.35 20.46 1687 33.67 9.72 18.30 (a) Find the sample mean The sample mean is Round to two decimal places as needed) (b) Find the sample standard deviation. The sample standard deviation is...
please show all steps 6.2.28-T The following data represent the concentration of dissolved organic carbon (mg/L) collectted from 20 samples of organic soil. Assume that the population is normaly distrbuted. Complete parts (a) through (c) on the right 17.50 29.80 16.87 14.86 27.10 20.46 520 16.51 1750 33.67 9.72 18.30 881 30.91 19.80 14.90 15.35 11.40 14 86 8.09 (a) Find the sample mean The sample mean is 17.58 (Round to two decimal places as needed.) (b) Find the sample...
The following data represent the concentration of dissolved organic carbon (mgt) collected from 20 samples of organic sol. Assume that the population is normaly distrbuted. Complete parts (a) through (c) on the right 17.50 3367 9.72 18.30 16.51 27.10 29.80 11.90 14 86 146 15.42 14.90 20 46 881 15.35 11.40 30.91 7 40 8.09 19 80 (a) Find the sample mean The sample mean is (Round to two decimal piaces as needed) (b) Find the samrple standard deviation The...
In a study on infants, one of the characteristics measured was head circumference. The mean head circumference of 14 infants was 34.6 cm. Assuming that head circumferences for infants are normally distributed with standard deviation 2.1 cm, determine a 95% confidence interval for the mean head circumference of all infants. Step 1: Determine ??/2. Step 2: Determine the CI. Step 3: Interpret the CI. Obtain the margin of error, ?, for the CI you found in part (a). Determine the...
The following data represent the concentration of dissolved organic carbon (mg/L) collected from 20 samples of organic soil. Assume that the population is normally distributed Complete parts (a) through (c) on the right 15.42 29.80 27.10 16.51 15.42 8.81 15.42 20.46 14.90 33.67 30.91 14.86 1750 15.35 9.72 19.80 14.86 8.09 15.42 18.30 (a) Find the sample mean The sample meanis L (Round to two decimal places as needed.) (b) Find the sample standard deviation The sample standard deviation is...