Question

Consider a sample that contains 3.95 g of Liz PO,. Determine the number of Lithium ions, the total number of ions, and the number of grams of both oxygen and phosphorous in the sample. When you re ready match each parameter (on the left) to the correct amount (on the right). Premise Response Drag and drop to match 1 number of Lions = A 1.64x10" 2 total number of ions = B 6.16x102 3 grams of O = C 1.06 4 grams of P = D 2.18

Answer 1

Ans :

Moles of Li3PO4 = mass / molar mass

= 3.95 g / 115.79 g/mol = 0.034 mol

each mol has three mol of Li+ ions , so here mol of Li+ = 3 x 0.034 mol = 0.102 mol

each mol has 6.022 x 10²³ ions , so Li+ ions will be :

= 0.102 mol x 6.022 x 10²³ ions /mol

= 6.16 x 10²² Li⁺ ions

each mol compound has three mol Li+ ions and one mol PO4^3- ions , so 4 ions per mol

so total mol ions = 0.034 mol x 4 = 0.136 mol ions

total number of ions = 0.136 mol x 6.022 x 10²³ ions/mol

= 8.22 x 10²² total ions

Each mol compound has 4 mol O

so 0.034 mol compound will have : 0.034 mol x 4 = 0.136 mol O

mass of O = mol x molar mass

= 0.136 mol x 15.999 g/mol

= 2.18 grams O

Each mol compound has one mol P

so mol P = 0.034 mol

mass of P = 0.034 mol x 30.97 g/mol

= 1.06 grams P

So here , correct matching will be :

1) Number of Li+ ions = 6.16 x 10²²

2) total number of ions = 8.22 x 10²²

3) Grams of O = 2.18

4) Grams of P = 1.06