Ans :
Moles of Li3PO4 = mass / molar mass
= 3.95 g / 115.79 g/mol = 0.034 mol
each mol has three mol of Li+ ions , so here mol of Li+ = 3 x 0.034 mol = 0.102 mol
each mol has 6.022 x 1023 ions , so Li+ ions will be :
= 0.102 mol x 6.022 x 1023 ions /mol
= 6.16 x 1022 Li+ ions
each mol compound has three mol Li+ ions and one mol PO43- ions , so 4 ions per mol
so total mol ions = 0.034 mol x 4 = 0.136 mol ions
total number of ions = 0.136 mol x 6.022 x 1023 ions/mol
= 8.22 x 1022 total ions
Each mol compound has 4 mol O
so 0.034 mol compound will have : 0.034 mol x 4 = 0.136 mol O
mass of O = mol x molar mass
= 0.136 mol x 15.999 g/mol
= 2.18 grams O
Each mol compound has one mol P
so mol P = 0.034 mol
mass of P = 0.034 mol x 30.97 g/mol
= 1.06 grams P
So here , correct matching will be :
1) Number of Li+ ions = 6.16 x 1022
2) total number of ions = 8.22 x 1022
3) Grams of O = 2.18
4) Grams of P = 1.06
Consider a sample that contains 3.95 g of Liz PO,. Determine the number of Lithium ions,...
Perform the following conversions. Match each calculation (on the left) to the correct value (on the right). Premise Response Drag and drop to match 5.6x1027 molecules of PO 10 to total → = A 7.84x1028 number of atoms. 2 9.50 moles of copperfil) phosphate to P atoms B 5.72x1024 8.7x1020 formula units of PbCl, to moles of ions = ( 1.14x1025 = D 1.72x1025 = 1.444x10-3 [ Fullscreen = F 2.24x10 = G 7.224x10-3