Question

Mesitylene, a hydrocarbon found in crude oil, has an empirical formula of C:H, and experimentally determined molecular weight of 121 u. what is its molecular formula? a- CH4 b-CH C- CH2 d-C12H 37) How many chlorine atoms are in 12.2 g of CCI a-4.77 x 102 b-7.34 x 1024 c-1.91 x 1023 d-2.07 x 1023 38) What is the molar mass of glucose CH 206 a- 180.0 g/mol b- 24.0 g/mol c- 72.0 g/mol d-96.0 g/mol 39) The mass in gram per mole is a- Molar mass b-density d-volume C-empirical formula 40) The percentage of carbon in C12H201 is a-42.1% b-6.4% c. 51.5% d-18.6% Good luck

Answer 1

molar mass of Empirical CC a Hu] = 40.06 g/mol molas mass ob moleculat formula = 1218%, ratio of molecular to empirical ? 40.oo Amol = 3 : moleculas fort mulai (3x3 Muxg Ans)' O"catie" Ca Hiz ... mas mass mass of cclu = 12:29 molao mass of cclu= 153-8% out 12-29 nolab mass 153.8 Ilmol - =0.079 met eclut ic and 4 cl's 0.ola mol stlax ucis -= 0. 317 bol cis R I calu In a mol 6.022x10 23 atoms presenta 0.311 mola 1 In

we have 2.3 0.317 mok* frozex todos metine = "1.91 81023 chlorine ..An-1.91 X2623 17 XL atoms Presents - cL atoms C6H12O6 molaco mass ³ 6x olao mass of c= 6x 12.0107 g/mol 12x nolao mass of H = 12 y 1.007 au g/mol 6x nolas mass of o= 6x 15-aaga /mol molao mass of Il me C6H12% = 180. 15588 180 09/met a" 180.0 limut. Ang' ID in nolas mass : mass at 1 molat mass 108) mass a mole gram in substante per mole . An) - a molar mass

C12H2zo1 v nolao mass of C12 H2O = 342. 39% molat massa carbons in sucrose = 12x 12.0107 g/mol = 144.1 g Percent of carbon = I total molat mass of copban molao mass of X100/ compound - 144.1 g/mol - X 100 y. 342. 39/mol . 42.1% (m/m) 2. Any), a 42.14