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A 101 g wooden block is initially at rest on a rough horizontal surface when a 11.2 g bullet is fired horizontally into (but

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Answer #1

Combined mass = 101 + 11.2 = 112.2 g

acceleration of friction = 0.750 * g = 7.35 m/s2

V after collision = sqrt(2 * a * s) = sqrt(2 * 7.35 * 6.5) = 9.77 m/s

Mb * Vbc = (Mw + Mb) * Vac

=> 11.2 * Vbc = 112.2 * 9.77 = 97.87 m/s

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