The company wants to sell t-shirts and owner wants to be 95% certain of the results, and she wants to be within $1,000 of the true mean. When she was researching online, she found that the standard deviation of the mean t-shirt sales for businesses similar to hers was $2,200.
How many should she get data from?
Solution :
Given that,
standard deviation = =
=2200
Margin of error = E = 1000
At 95% confidence level the z is ,
= 1 - 95% = 1 - 0.95 = 0.05
/ 2 = 0.05 / 2 = 0.025
Z/2
= Z0.025 = 1.96
sample size = n = [Z/2*
/ E] 2
n = ( 1.96* 2200 / 1000 )2
n =18.59
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