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An instructor has given a short quiz consisting of two parts. For a randomly selected student, let X - the number of points e
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Answer #1

a) First we find the marginal distributions and Expectations of X and Y each

X 0 5 10
P(X) 0.21 0.51 0.28
x.P(X) 0 2.55 2.8

E(X) = ∑x.P(X) = 0 + 2.55 + 2.8
         = 5.35
E(X) = 5.35

Y 0 5 10 15
P(Y) 0.08 0.38 0.33 0.21
y.P(Y) 0 1.9 3.3 3.15

E(Y) = ∑y.P(Y) = 0 + 1.9 + 3.3 + 3.15  
         = 8.35  
E(Y) = 8.35  
  
E(X + Y) = E(X) + E(Y)  
          = 5.35 + 8.35  
          = 13.7  
E(X + Y) = 13.7  

b)    Let Z = max(X, Y)
We find the probability of Z by summing up the probabilities given for max value of X or Y      
e.g. Z= 5 => max (X, Y) = 5 thus we sum up probabilities for (X = 0, Y = 5), (X = 5, Y = 5), (X= 5, Y = 0)      
                                                                                         = 0.06 + 0.17 + 0.04

Z 0 5 10 15
P(Z) 0.03 0.27 0.49 0.21
Z.P(Z) 0 1.35 4.9 3.15

E(Z) = ∑z.P(Z) = 0 + 1.35 + 4.9 + 3.15
         = 9.4
E(Z) = 9.40

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