Homework Answers
Horizontal component of field, Bx = 5 x 10^-5 cos(44)
Bx = 3.6 x 10^-5 T
Vertical component of field,
By = (5 x 10^-5 sin(44)) - (4 pi x 10^-7 x 25/2 pi x 0.21)
By = 1.09 x 10^-5 T
Net magnetic field, B = sqrt(Bx^2 + By^2) = 3.76 x 10^-5 T
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