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Problem 28.9 3 of 12 Constants | Periodic Table A long horizontal wire caries 25.0 A of current due Part A north What is the

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Answer #1

Horizontal component of field, Bx = 5 x 10^-5 cos(44)

Bx = 3.6 x 10^-5 T

Vertical component of field,

By = (5 x 10^-5 sin(44)) - (4 pi x 10^-7 x 25/2 pi x 0.21)

By = 1.09 x 10^-5 T

Net magnetic field, B = sqrt(Bx^2 + By^2) =​​ 3.76 x 10^-5 T

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