The x and the y components of the electric field at point P will be as shown below:
Now,
the x component will be
By integrating we get
similarly the y component of the electric field will be
by intergrating we get
Now the angle will be
by plugging all the values we get
which gives us
or
which is independent of R
in rind the Mass of the Earth Problem 3. A "semi-infinite" non-conducting rod (that is, infinite...
In the figure below, a "semi-infinite" nonconducting rod (that is, the rod is infinite only in the positive y direction) has uniform positive linear charge density lambda. Two particles with charges +Q are located at distances a from the origin as shown. Remember: You must show every step of your calculations! What are the x- and y - components of the electric field produced by the rod at the origin? Show your work for calculating the electric field by labeling...
A thin glass rod is a semi-circle of radius R. a charge is non-uniformly distributes along the rod with a linear charge density given by lambda = lambda_0 cos(theta) where lambda_0 is a positive constant Point P is at the center of the semi-circle. Find the electric field (magnitude & direction) at point P.
8 A semi-infinite thin rod has a uniform linear positive charge density λ and is located along the x-axis between x = x° (>0) and x = +ㆀ. Find the electric field at the origin. Hint: Ja .2 = a-b A.의 dx 1 B. 一巡i E. zero 8 A semi-infinite thin rod has a uniform linear positive charge density λ and is located along the x-axis between x = x° (>0) and x = +ㆀ. Find the electric field at...
tions... And finally, Qa-F and ecr are not equal, and ehe I S ) The diagram shows a short rod (red) resting a distance a above and perpendicular to an infinite non-conducting sheet (green) with charge density The rod has a non-uniform charge density on it, and a total charge Qo Assuming that a small element of charge on the red rod is dq-An(r)dr, and given that its density is of the forn AR(r)-b sin(π,a), calculate the value of the...
1) In Millikan's experiment, an oil drop of radius 1.95 μm and density 0.857 g/cm3 is suspended in chamber C (see the figure) when a downward electric field of 1.36 × 105 N/C is applied. Find the charge on the drop, in terms of e. 2)In the figure a “semi-infinite” nonconducting rod (that is, infinite in one direction only) has uniform linear charge density λ = 1.38 μC/m. Find (including sign) (a) the component of electric field parallel to the...
PROBLEM 02.05 A uniform current with the surface current density K flows along an infinite conducting plane. The plane is adjourned on one of its sides by an infinite plate of finite thickness d made of a non-conducting linear material with magnetic permeability p Find the magnetic field B, the H-field, the magnetization M, and all bound currents ir everviwhere
In the figure at the right, a non-conducting rod of length L = 12.0 cm has a charge –q = –3.24 fC uniformly distributed along its length. Point P is at a distance a = 8.15 cm from the rod. (a) What is the linear charge density of the rod? (b) What is the magnitude of the electric field produced at point P? (c) What is the direction (relative to the positive direction of the x-axis) of the electric field...
QUESTION 21 Parallel conducting tracks, separated by 2.50 cm, run along yaxls. There is a uniform magnetic field of B = 3.75 T pointing along 2-axis (out of the pagel. A cylindrical metal rod is placed across the tacks along x-axis and a battery is connected between the tracks, with its positive terminal connected to the left track of the current through the rod is 71.75 A find the magnitude Fand direction of the magnetic force on the rod. Cylindrical...
5. (10 points) Two parallel semi-infinite sticks, a distance 2b apart, are joined by a semicircular piece of radius b, as shown below. A constant linear charge density λ is deposited along the whole of the arrangement. Find the electric field E; at the center of the semicircle.
5. (10 points) Two parallel semi-infinite sticks, a distance 2b apart, are joined by a semicircular piece of radius b, as shown below. A constant linear charge density λ is deposited along the whole of the arrangement. Find the electric field E at the center of the semicircle.