Question

(3 points) Four charged beads are arranged in a diamond centered at the origin. Each of the beads is 0.9cm from the origin in one of the cardinal directions. The bead above the origin has a charge of +210nC, the bead to the right of the origin has a charge +590nC, the bead below the origin has a charge +210nC, and the bead to the left of the origin has charge -590nC. A ball bearing with a charge +60nC is placed at the origin. Using the convention that i is right and j is up, what is the force on the ball bearing in component form? Ni+ Nj How much electric potential energy does the ball bearing have?

Answer 1

Force will be only due to 590 nc charges and p.e will be only due to 290 nc charges .

Force = -7.8666 N i + 0 N j

P.e = 0.0348 J

Force will be only due to 590 nc charges and p.e will be only due to 290 nc charges . Force = -7.8666 N i + 0 N j P.e = 0.0348 J \r\n Vertical-bar F_1 vector Vertical-bar = Vertical-bar F_2 vector Vertical-bar So, F_net = F_3 vector + F_4 vector Vertical-bar F_3 vector Vertical-bar = Vertical-bar F_4 vector Vertical-bar F_net vector = 2 Vertical-bar F_3 vector Vertical-bar (-i^cap) F_net = 2 times k times 60 nc times 590 nc/(0.9 times 10^-2)^2 (-i^cap) F_net = 2 times 9 times 10^9 times 60 times 10^-9 times 590 times 10^-9/8.1 times 10^-5 - i^cap F_net = -78666 N i^cap + 0 N j^cap P.E = k q_1 Q_2/r = 2 times 9 times 10^9 times 60 nc times 290 nC/0.9 times 10^-2 (As- 590 nc & 590 nc unit zero) P.E = 0.0348 J