SOLN 5
pH = -log (H3O+)
hence H3O+ = 10-pH
(a) at pH = 0 H3O+ = 10-0 =1.00 M
(b) at pH =7.00 H3O+ = 10-7 =1.00 * 10-7 M
(c) at pH = 2.63 H3O+ = 10-2.63 = 0.00234 M
(d) at pH = -0.42 NOT POSSIBLE (assuming solvent to be water)
(e) at pH =11.21 H3O+ = 10-11.21 =6.16*10-12 M
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