Homework Answers
pH = 4.7
Ka = 3.04 x 10^-5
pKa = -log Ka = 4.517
concentration of HA = NaA = 0.10 M
volume of HA = x
volume of NaA = 10 - x
pH = pKa + log [salt / acid]
4.7 = 4.517 + log [10 - x / x ]
[10 - x / x ] = 1.524
10 - x = 1.524 x
x = 3.96
volume of HA = 3.96 mL
volume of NaA = 6.04 mL
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Basically, we desire to have a ph of 4.7, from an acid of 0.1M
and a conjugate base of 0.1M. Ultimately our solution should have a
total volume of 0.01 L, and we have a ka of 3.04x 10^-5. However I
do not know how to find [HA]/ [A-] in the the buffer and how to
find the volume of 0.1 M HA/ volume 0.1 M A- needed on buffer.
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