No of mol of HCl added = 10*0.2 = 2 mmol
No of mol of NaOH taken = 30*0.05 = 1.5 mmol
No of mol of excess HCl = 2-1.5 = 0.5 mmol
concentration of HCl = 0.5/40 = 0.0125 M
pH = -log[H+]
= -log0.0125
= 1.9
if 10ml of 0.200 M Hcl is added to 30ml of 0.0500 M naoh, what is...
25. If 10.00 mL of 0.200 M HCl is added to 30.0 mL of 0.0500 M NaOH, what is the ph of the solution? Show all work for full credit. (6 pts)
25. If 10.00 mL of 0.200 M HCl is added to 30.0 mL of 0.0500 M NaOH, what is the solution? Show all work for full credit. (6 pts)
25. If 10.00 mL of 0.200M HCl is added to 30.0 mL of 0.0500 M NaOH, what is the pH of the solution? Show all work for full credit. (6 pts)
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