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if 10ml of 0.200 M Hcl is added to 30ml of 0.0500 M naoh, what is...

if 10ml of 0.200 M Hcl is added to 30ml of 0.0500 M naoh, what is the ph of the solution?
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Answer #1


No of mol of HCl added = 10*0.2 = 2 mmol

No of mol of NaOH taken = 30*0.05 = 1.5 mmol

No of mol of excess HCl = 2-1.5 = 0.5 mmol

concentration of HCl = 0.5/40 = 0.0125 M

pH = -log[H+]

   = -log0.0125

   = 1.9

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