Solution :
=> Answer :- Option a. 0.015
Given that n = 4 , x = 3 , p = 1/6 = 0.1667
=> q = 1 - p = 0.8333
=> P(x = 3) = 4C3*(0.1667^3)*(0.833^(4 - 3))
= (4!/3!*1!)*(0.1667^3)*(0.833^(4 - 3))
= 0.0154
= 0.015 (rounded)
Formula :
=> For binomial distribution , nCr*p^r*q^(n-r)
nCr = n!/(r!*(n-r)!)
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