SolutionA:
P(Ac)=1-P(A)
=1-0.25
=0.75
ANSWER:0.75
Solutionb:
P(AUB)=P(A)+P(B)-P(A and B)
P( A and B)=P(A)*P(B) since both are independent events since outcome of one event does not effect the outcome of other
therefore
P(AUB)=0.25+0.65-0.25*0.65
P(AUB)=0.7375
ANSWER:0.7375
Solutionc:
P(AUB)c= 1-P(AUB)
=1-0.7375
=0.2625
ANSWER:
0.2625
PROBLEM 4.2 (pg 63, #17) Let A denote the event that the next request for assistance...
Consider randomly selecting a student at a certain university, and let ? denote the event that the selected individual has a Visa credit card and ? the analogous event for a MasterCard. Suppose that ?(?) = 0.5, ?(?) = 0.4, and ?(? ∪ ?) = 0.65. a. What is the probability that the student has both types of cards? b. What is the probability that the student has a MasterCard but not a Visa? c. What is the probability the...
5. Let A denote the event that the next item checked out at a college library is a math book, and let B be the event that the next item checked out is a history book. Suppose that P(A) 40 and P(B50. a. Why is it not the case that P(A) P(B) 1? b. Calculate P(A) c. Calculate P(A U B). d. Calculate P(4'n B).
Consider randomly selecting a student at a certain university, and let A denote the event that the selected individual has a Visa credit card and B be the analogous event for a MasterCard where P(A) = 0.45, P(B) = 0.35, and P(A ❩ B) = 0.30. Calculate and interpret each of the following probabilities (a Venn diagram might help). (Round your answers to four decimal places.) (a) P(B | A) (b) P(B' | A) (c) P(A | B) (d) P(A' | B) (e) Given...