F) 50 ml buffer contains 25 ml CH3COOH,25 ml
CH3COONa.
No of mol of CH3COOH = 25*1 = 25 mmol
No of mol of NaOH = 25*1 = 25 mmol
after addition of NaOH,
pH of acidic buffer = pka + log(CH3COONa+NaOH/CH3COOH-NaOH)
pka of CH3COOH = 4.74
No of mol of NaOH added = 2*1 = 2 mmol
pH = 4.74+log((25+2)/(25-2))
pH = 4.81
Theoretical pH = 4.81
2) Measured (Experimental) pH = 4.59
Theoretical pH = 4.81
%error = (Theoretical- Experimental)/Theoretical*100
= (4.81-4.59)/4.81*100
= 4.57%
F. pH of Buffer after the addition of the Strong Base 1. Calculate the expected pH...
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