Given:
Hof(H2(g)) = 0.0 KJ/mol
Hof(O2(g)) = 0.0 KJ/mol
Hof(H2O(g)) = -241.818 KJ/mol
Balanced chemical equation is:
2 H2(g) + O2(g) ---> 2 H2O(g)
ΔHo rxn = 2*Hof(H2O(g)) - 2*Hof( H2(g)) - 1*Hof(O2(g))
ΔHo rxn = 2*(-241.818) - 2*(0.0) - 1*(0.0)
ΔHo rxn = -483.636 KJ
Answer: -483.64 KJ
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