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2. A very thin, flat, uniform slab has a width (W) of 2.00 m, a height (H) of 30.0 cm, and a total mass of 16.0 kg. Treating the slab as essentially a sheet of mass- distributed uniformly over its area- do the following (i) Use integration to prove that the slabs center of mass is located at its center point. a. (Reminders: dm - ndA dA can be written here as either Hdx or Wdy What is the value of n here?) (ii) Now use integration to calculate Im , the moment of inertia of the slab about an axis through the center of mass (and that axis is parallel to the sides) (ii) Now, without integrating (i.e. by using the Parallel Axis Theorem and the previous result), calculate Lide, the moment of inertia of the slab about an axis along one side of the slab (and parallel to that side)

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