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just 18&19
The following questions refer to the reaction shown below: Initial Rate of Initial [A (mol/L) 0.16 Initial [B] (mol/L) 0.15 D
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Answer #1

(18) Rate = K[A][B] . 0.08 = K[ 0.168 (0.1572 K 5,76x109 . K = 0.08 = 138.8. 5.76x1ö9 ~ 140 Am @ 140 16 Ka Imor] in [litre]ht

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