Homework Answers
a:- induced emf e = -BdA/dt
e = - Bout d[(πa2/2π)θ]
e = - Bout (a2/2)dθ/dt
e = - Bouta2ω/2
b:- magnitude of induced emf
e = Bouta2ω/2
e = 0.500 * (0.050)2* 2.00
e = 0.00125 V
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