Question

QUESTION 3 1 points Save Answer The enthalpy change for the reaction of perchloric acid (HC104) and potassium hydroxide (KOH) is being studied. The reaction of 50.00 mL of 0.2520 mol/L HCIO4 with 50.00 mL of 0.3120 mol/L KOH in a coffee cup calorimeter resulted in a temperature change from 23.1 °C to 25.5 °C. The density of the solution is 1.040 g/mL, and the heat capacity of the solution is 4.158 J g-1 °C-1. Calculate the qsys for this reaction. Express your answer to 4 significant figures and in Click Save and Submit to save and submit. Click Save All Answers to save all answers. Save All Answers Close Window Save and Submit

Answer 1

L I volume of Haloq solution = v= 5o-ooml Volume of KOH solution = V2 = 50.00ml Total volume of solution = V = (V+V2) V = (50tsolmL = loomL Density (e) of solution = 1-040g|ml Mass of solution (m) = p Xv = 1-4 og/mL X loomL m= 14g Heat capacity of solution = c = 4.158 J goc Initial temperature = To = 23.100 final temperature = Tf = 25.5c change in temperature (AT) = 25.5c-23-1°C AT = 2.4°C 9 sys =Heat released = MCAT = 1049 X 4.158Jgx 2.4°C usys = 1037.835 Answer IKT = 1000 J sys = 1.0378 kJ