Find the kinetic energy of an electron whose de Broglie
wavelength is 40.0 nm.
7.07e16 J
The momentum of the electron is given by
p = sqrt (2mK)
where m is mass and K is kinetic energy
so,
= h / p
= h / sqrt (2mK)
squaring both sides, we have
2 = h2 / 2mK
K = h2 / 2m2
K = 6.63e-342 / 2 * 9.1e-31 * 40e-92
K = 1.51e-22 J
Find the kinetic energy of an electron whose de Broglie wavelength is 40.0 nm. 7.07e16 J
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