answer) first we have to find the kinetic energy lost by hammer
so K.E=n*1/2m12v2=5*1/2*1.49kg*(6.6m/s)2=162.261J
this energy is =Q
we know the formula
Q=m2*c*dT
c=450j/kg
dT=Q/m2c=162.261J/0.012*450=30oC
so the answer is 30oC or 30.05oC
The 1.49 kg head of a hammer has a speed of 6.6 m/s just before it...
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