a)
Ho : µ1 - µ2 = 0
Ha : µ1-µ2 > 0
Level of Significance , α = 0.05
mean of sample 1, x̅1= 9.3666
standard deviation of sample 1, s1 =
2.0996
size of sample 1, n1= 8
mean of sample 2, x̅2= 6.8916
standard deviation of sample 2, s2 =
1.5951
size of sample 2, n2= 8
difference in sample means = x̅1-x̅2 =
2.4750
pooled std dev , Sp= √([(n1 - 1)s1² + (n2 -
1)s2²]/(n1+n2-2)) = 1.86447
std error , SE = Sp*√(1/n1+1/n2) =
0.93223
t-statistic = (x̅1-x̅2)/SE =
2.65491
Degree of freedom, DF= n1+n2-2 = 14
t-critical value , t* =
1.7613
Decision rule : reject Ho , if | t-stat | > t-critical,otherwise
not
so, conclusion is reject Ho,
hence, there is enough evidence to claim that higher baking temperature results in wafers with a lower mean photoresist thickness.
b)
p-value = 0.00942
Conclusion: p-value <α , Reject null
hypothesis
9. Photoresist is a light-sensitive material applied to semiconductor wafers so that the circuit pattern can...
(a) Is there evidence to support the claim that the high- er baking temperature results in wafers with a lower mean photoresist thickness? Use α-0.05. (b) What is the P-value for the test conducted in part (a)? (c) Find a 95 percent confidence interval on the difference in means. Provide a practical interpretation of this interval (d) Draw dot diagrams to assist in interpreting the results from this experiment. (e) Check the assumption of normality of the photoresist thickness. (f)...