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Force (N) 40 1.00 60 8 0 Position (m) Find the work done by the force in moving the object from 0.40 m to 1.20 m. Explain you
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Answer #1

The work done and kinetic energy

work done = Area under f-s groph w = Area of parabola carre wz (width) x (height) w = 2 ( 1.20 -0.40) x (201) w = 1.12 I Acco

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