use:
Kb = Kw/Ka
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
Kb = (1.0*10^-14)/Ka
Kb = (1.0*10^-14)/8.9*10^-8
Kb = 1.124*10^-7
HS- dissociates as
HS- + H2O -----> H2S + OH-
0.0651 0 0
0.0651-x x x
Kb = [H2S][OH-]/[HS-]
Kb = x*x/(c-x)
Assuming x can be ignored as compared to c
So, above expression becomes
Kb = x*x/(c)
so, x = sqrt (Kb*c)
x = sqrt ((1.124*10^-7)*6.511*10^-2) = 8.553*10^-5
since c is much greater than x, our assumption is correct
so, x = 8.553*10^-5 M
use:
pOH = -log [OH-]
= -log (8.553*10^-5)
= 4.0679
Answer: 4.07
8 Question 8 Tries remaining: 2 Points out of 1.00 P Flag question What is the...
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