Question

Could someone please provide some working out for part c? Thanks!

An electric curent of 1.25 A is passed through a solution of copper (I) sulfate for 32.5 minutes. Calculate the mass of copper deposited on the cathode of the electrolytic cell by completing the fallowing three questions: a) What charge has passed through the electrolytic cell described above 2.44x 103 C Well done! Irsutticient infamation is pravided to caloulate charge. 86485 C 40.8 C 1/1 b) Using the correct charge calculated in part a), calculate the amount of electrons for this charge 253x 10 mal Wcl donc! 2.35 x 1a mo 96485 mo 1/1 c) Using the number of moles of electrons calculated in part b), calculate the mass of copper solid that will be deposited at the cathode. (Hint: consider the reduction half equation for the formation of oopper solid) O 63.5g O 1.81g O B04x 10g O 38x 10g Check

Answer 1

c) we know that mass deposited at the Cathode - can be given by the fomula! - wa kit см xГx 1 x46Гоо 1 , Mc Mala, Үсоці в Корея. y a "° Cu , , Cu + + 4 ) I= current = 1.25 A to me 32. °) : 32-x 60 сес wa mas depose ted. #о (5 : 62.5 х 1: 25 x 32-5 xbo 2х46 Гоо 15 478 ( - 25 14 2000 О. (ОА И • 04 0 (0 3 в с