Question

i also dont get how to do the rest of the problem. thank you for the help

5.4.T1 Question Help For the following situation, find the mean and standard deviation of the population. List all samples (with replacement) of the given size from that population and find the mean of each. Find the mean and standard deviation of the sampling distribution and compare them with the mean and standard deviation of the population. The word counts of five essays are 510, 636, 551, 607, and 578. Use a sample size of 2. D The mean of the population is 576.4. (Round to two decimal places as needed.) The standard deviation of the population is (Round to two decimal places as needed.) Enter your answer in the answer box and then click Check Answer.

Answer 1

SOLUTION:

From given data,

510

636

551

607

578

The Mean of the population is

$\bar{x}$ = $\Sigma$ x / n

= (510+636+551+607+578)/2

= 2882/5

= 576.4

The standard deviation of the population is

s = sqrt($\Sigma$ (x-$\bar{x}$)² / (n-1) )

s = sqrt((510-576.4)²+(636-576.4)²+(551-576.4)²+(607-576.4)²+(578-576.4)²)/(5-1) )

s = sqrt(9545.2 /4 )  

s = 48.85

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