Question

A turbine spins at initial angular velocity of 1.25 X 10' rev/min. When a 175 N.m torque is applied, the turbine comes to a complete stop in 187 s. The moment of inertia of the turbine is equal to a. b. c. 0.436 kg .m2 4.17 kg.m? 26.2 kg.m 122 kg.m 250 kg. m d. - Ito annular

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Answer 1

. We know that if Wi & We are the initial & final angular velocity & x is the angular acceleration & t is the duration of tine ther, as + . t Wis 1.25x 10% bermin given, wraa kta 1875. acceleration so, magnitude of angular W, 1.25x1032210 - 60 2- nad/st 187 nassez - az 1.25 x 10²x22 60 x 187 1. So, the magnitude of tonane c= 1a, where I is the monent of inertia of the turbine

ginen, P=175 nom ka.ma herce ; I = 125*60*187 7:25.7 103x22 3) I = 250.000 5846 kg.me 2= 250 kg, m? (appron) connect option is €) 250 kg. m2 so,