Question

1) A container is filled to the brim with 1.4 L of mercury at 20 C. The coefficient of volume expansion of mercury is 1.8x104 (C). As the temperature of the container and mercury is increased to 49 C, a total of 7.5 ml of mercury spill over the brim of the container, Determine the linear expansion coefficient of the material that makes up the container K Submit You currently have 2 submissions for this question. Only 5 submission are alowed. You can make 3 more submissions for this question.

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Answer 1

In this problem first we can find the,

increase in volume of mercury then we will find out the,

increase in volume of container and then find coefficient of linear expansion is r/3.
In this problem first we can find the, increase in volume of mercury then we will find out the, increase in volume of container and then find the coefficient of linear expansion is r/3. \r\n Given that, A container is filled with mercury of 1.4l = 1.4 times 10^-3 k l at 20 degree c coefficient of volume expansion of mercury is, 1.8 times 10^-4 (degree C)^-1 Increased temperature = 49 degree C. spilled mercury = 7.5ml. So, Increase in volume of mercury, = 1.4 times 10^-3 kl times 1.8 times 10^-4 (degree C)^-1 times (49 degree C - 20 degree C) = 2.52 times 10^-7 times (29 degree C) = 73.08 times 10^-7 m^3 rightarrow (1) Increase in volume of container, = 1.4 times kl times r (49 degree C - 20 degree C) = 1.4 times 10^-3 times r times 29 degree C = 40.6 times 10^-3 r m^3 rightarrow (2) \r\n Given that, from (1) and (2), -73.08 times 10^-7 m^3 + 40.6 times 10^-3 r m^3 = 7.5 times 10^-6kl