Question

Determine when and where A will overtake B. (Round the time to two decimal places and the position to the nearest whole number.) (You must provide an answer before moving to the next part.)

A will overtake B after s at x = ft.

determine a) when and where A will overtake B, b) the speed of each automobile at that time.

TechnoCad- CAM ENVIRONMENT TECHNOREV4000- [W-SO14700217C. BDF) Fle Edr ew Hstory Bookmarks Toos Help E Course Mod Module 1 Assign..x E Course Modules:.+ Thickness n.com/hrn.tpx Search Questions 45 (of 10) Save & Exit Submit ▼ Use the sub navigation below to navigate within this series of questions. answer & continue> Problem 11.042 - Uniformly accelerated motion of two particles - DEPENDENT MULTI-PART PROBLEM- ASSIGN ALL PARTS Automobiles A and Bare traveling in adjacent highway lanes and at t-0 have the positions and speeds shown. Know that automobile A has a constant acceleration of 2 ft s2 and that Bhas a constant deceleration of 1.4 fts2 (24 mi/h Bo-36 mi/h 75 ft Absolute coordinates X: 1862040 m Y: -13.92? mm References eBook & Resources start 9:53 AM

Answer 1

We can have the expressions for positions of cos A & B as! x_A = v_0 A + 1/2 a_A t^2 + a_A0 [24 mph = 35.2 ft/s & 36 mi/h = 52.8 ft/s] = x_A = 35.2 t + 1/2 (2) t^2 + 0 * x_A = 35.2 t + t^2 & x_B = 52.8 t + 1/2 (minus 1.4) t^2 + 75 = x_B = 52.8 t minus 0.7 t^2 + 75 (a) A overtakes B at t = t_1 & at that time x_A = x_B 35.2 t_1 + t^2_1 = 75 + 52.8 t, minus 0.7 t^2_1 = 1.7 t^2_1 minus 17.6 t_1 minus 75 = 0 t_1 = 17.6 + squareroot 17.6^2 minus 4 (1.7) (minus 75)/2 (1.7) = 13.60 s x_A = 35.2 (13.60) + (13.60)^2 = 664 ft A will overtake B after 13.60 s at x = 664 ft