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At a certain distance from a charged particle, the magnitude of the electric field is 516 V/m and the electric potential is -2.40 kV. (a) What is the distance to the particle? (b) What is the magnitude of the charge? HCneed help in solving this. thank you

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516 V/ r= k6- -2.to kv 5 16 2.40Xlo 5 16 2-40x1。3 = (3x109 )(6) 4-6 5 1. 2403 ,UL

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