Question

Physics 114 - Exam 2, Dynamics of ParticlesSHOW YOUR WORK Name: Force Balance and Free body Diagrams (continued) 15. (3) Fill in the each blank with a word(s) chosen from below: zero sum change 2 Law newton normal free body A net force acting on a body will cause a to the motion of the body. In a dynamic analysis, all forces acting on a body are identified and shown as vector components on a _diagram. The net force for each the x and y direction is evaluated as the of the forces in those directions. When the net force is nonzero, then Newton's identifies that force is equal to mass of the body times its acceleration. When the net force in both the x and y directions is then the body is said to be in equilibrium. 16. (6) Solve for the acceleration of the box in the illustration below if the hanging mass is 10 kg and the box mass is 30 kg. Gravitational acceleration is 9.8 m/s

Answer 1

15.

1. change

2. Free body diagram

3. components

4. law

5. zero

16.

..................(I)

T = 300

...................(II)

10g - T = 10a

10g – 30a = 10a

10g 9. 8 2 a = 40 =ā m/s2

a = 2.45 m/s