Suppose obtain the value of S if d=8, g=0.03, k=0.07, and n=10. Round your final answer to two decimal places.
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This is a geometric progression with first term (a) as d/(1+k) and common ratio (r) as (1+g)/(1+k) and number of terms (n) as n+1
The sum for n+1 terms is a*(1-r^(n+1))/(1-r)
Here sum will be d/(1+k)*(1-((1+g)/(1+k))^(n+1))/(1-(1+g)/(1+k))=8/1.07*(1-(1.03/1.07)^11)/(1-(1.03/1.07))=68.4721
Suppose obtain the value of S if d=8, g=0.03, k=0.07, and n=10. Round your final answer...
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