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S22-1 An imaginary, spherical surface has radius 5.0m and is centered on the origin. A +15.0nC point charge is located on the x-axis at position x=+6.0m. There are no other charges in the region. . Calculate the electric field on the spheres surface at location x- +5.0m · Calculate the electric field on the spheres surface at location x= -5.0m According to Gausss Law, the total electric flux through the spheres surface is zero since there is no charge inside the sphere. How is this possible if the electric field is so much stronger on one side of the sphere? Use a sketch to explain your reasoning.

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SP mag -5m im (a) Field at A is ElE4TEC,ア um 2. E= 135 NC (G) Field at B i E, (l101 E135 (.15 N 121 E-.lI57NC →The net efectouc flux through imaginary sphere. is zero eventhough a stsung electoic feld exisbx beside it. This is because the namben cf feld lives entosung the sphovus fram +1snc cheage is equal to numb ot to numbe f feld line, leaving tla spheve: Henco lbato

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