Question

Consider the table below. Age Group Frequency 18-29 9831 30-39 7845 40-49 6869 50-59 6323 60-69 5410 70 and over 5279 What is P(30-49’)? 35.4% 18.9% 76.3% 64.6%

Answer 1

answer:

given data,

the age group frequency's is $\Rightarrow$ 18-29 9831, 30-39 7845, 40-49 6869, 50-59 6323, 60-69 5410, 70 and over 5279.

to find the P(30-49’) ...?

$\Rightarrow$now here we are know as the values is already

$\Rightarrow$the probability is shown in the below...

now we are need the find the total frequency is,

$\Rightarrow$ 9831+7845+6869+6323+5410+5279

$\Rightarrow$41557

$\Rightarrow$now the probability of the P(30-49’) is,

$\Rightarrow$7845+6869

$\Rightarrow$14714

$\Rightarrow$now we are know as the formula is $\Rightarrow$ age groups / total frequency

$\Rightarrow$now substitute the values is in the above formula

$\Rightarrow$14714 / 41557

$\Rightarrow$0.35406 * 100

$\Rightarrow$35.4%

$\Rightarrow$therefore 35.4%

$\Rightarrow$so finally the option a is correct answer 35.4%

35.4%