Question

ULO E 3 A compound of sodium and sulfur is analyzed to contain following mass of each elements. Calculate is the empirical formula. Show all calculation steps by using conversion factor, give calculator value (c.v.) and Final value (f.v) to get full credit. Show steps (1.2,3) (Na = 5.891 g and S = 4.109 g) 6 pt Step 1: Step 2: Step 3: Empirical Formula is: 4 in the following chemical reaction. Balance the molecular equation by adding coefficier Write the net ionic equation by adding phases. Do not write ionic Eq. (4 pts) Molecular Eq.: 3HNO: (aq) + Alom

Answer 1

- Step 1: mass of Na = 5.891g molar mass of Na-22.98 g/mol Mass of s = 4.109 g. Molar mass of s = 32.065 g/mol Step 2 8 moles of Nae mass i = 3.891g molare mass - 22.98 g/mol i moles of Na= 0.256 mol s = moles of s = mass = 4 los grue Nos moles of molae mass moles of s = 0.128 mol step 3: Convension factor Divide by small whole Number am moles of Na: moles of s . 0.128 0.256 : Empoucal formula is Nas