A. 2 HClO4 + Ca(OH)2 = Ca(ClO4)2 + 2 H2O
Mmoles of HClO4 = 2* mmoles of Ca(OH)2
Mmoles = molarity* volume
0.115 * V = 50.00 * 0.0875 *2
V = 76.1 ml
B. Moles of NaOH = mass / molar mass
= 3.2 / 40
= 0.08
Molarity = moles / volume ( in L)
= 0.08 / (20*10^-3)
= 4.0 M
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