Question

Suppose a large shipment of radios is sampled for quality and that 3 out of 5 sampled are found defective. Let's assume the Binomial model holds for X, the number of defectives. Review the Binomial model Bin(n, p). Consider a whole range of possible values and then try to pick up the one that gives highest probability of obtaining X=3.

Find P(X=3) when p=0.1

Answer 1

Here we have n=5 and p=0.10. So the required probability is

$P(X=3)=\binom{5}{3}(0.1)^{3}(1-0.1)^{5-3}=0.0081$

Answer: 0.0081