Question

Consider an element that reaches its first excited state by absorption of 413.9 nm light Determine the energy difference in kilojoules per mole between the ground state and the first excited state. AE = kJ/mol If the degeneracies of the two states for the element are g*/go = 2, determine N*/No at 2070 K No By what percentage does N*/No change if the temperature is raised by 20 K? % percentage: What is N*/No at 5040 K? No

Answer 1

According to Planek, DE =h2 brequency c speed of night - he wave length h plenektontont. C) DE 6.626x1038 3X108 that 418.9x10-9 _6-62671634 X 3x108 413-9810-9 = 4.80 X 10-19) ( 1KJ = 1100 J) =4.80 X18-22 kJ (1h in degenerate cone Boltzmon distribution formulas genty- where ni population of ith state. no population of mount state. gi degeneracy of ith state. go → degonorary of groun a state DEL = Ei-E. KB Boltzmann contomt 4 = 1.38x10-23 J/K T tomparature in kelvin scale. NONN 4.80 x 10-198 more on Tr eening = axe- 1.38x10-23 7/47 207014 Box 1.01710-7 CM HT=(2070+ 20) = 2040 K them from eye. 1 we get, 4.80 x 10-198 N* = 2xe- 1:38X102) fishy 209018 - 1.18810-7 , HP X10-7--01X107 % of change = 1.01810- 7 1 = 16.83 %. x 100%

(IN T= 5040 K then from ear N = 2e- we get, 3 - 4 x 1 x 50407 SB 2.01810-3