Here,
let the distance from center of the planet X is r
Now, as Time period of the satellite , T = 4 daya
for the formula of time period
T^2/r^3 = 4pi^2/(G * M)
(4 * 24 * 3600)^2/r^3 = 4pi^2/(6.673 *10^-11 * 9 *10^23)
solving for r
r = 5.664 *10^7 m
the distance of satellite from the planet X is 5.66 *107 m
-----
b)
find the speed of the satellite is v
v = sqrt(G * M/r)
v = sqrt(6.673 *10^-11 * 9 *10^23/(5.664 *10^7))
v = 1029.72 m/s
the speed of the satellite is 1029.72 m/s
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