Question

this is the correct answer. please show the work for this.

Referring to the image below, if Force A = {3.0} N, Force B = {27.0} N, P = {115.0} degreesas measured from the +X-axis, Ra= (3.6} cm, and Rb={11.8} cm, what will Force C have to be if it is to keep the wheel in the image from moving? 3 SigFigs with units and sign. -5.24*N Your last answer was interpreted as follows: -5.24\,\mathrm{N} The units found in your answer were: \left( \mathrm{N} \right)

also, please plug your work into the calculator to make sure it was right. i have posted this before and was given incorrect work.

Answer 1

to keep the wheel from rotating

torque due to A + torque due to B + torque due to C = 0

3* 11.8 - 27 * 3.6 - 11.8 Fc = 0

Fc = - 5.237 N

Fc = - 5.24 N

negative sign indicates that the torque corresponding to this forces is in clockwise way

======

Comment before rate in case any doubt, will reply for sure.. goodluck