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8. The cesium iodide (CsI) molecule has an atomic sepa ration of 0.127 nm. (a) Determine the energy of the second excited rot

8. The cesium iodide (CsI) molecule has an atomic separation of 0.127 nm. (a) Determine the energy of the second excited rotational state, with J 5 2. (b) Find the frequency of the photon absorbed in the J 5 1 to J 5 2 transition.

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I comes Centre of Moss k = 0.1271 Moment of Wertats about yans I = (132-9 * 114.8 x 1066*10 + (0-127) x 10 132.9 + 114.8. I

Ephoton = 4 Enot E, -E;-) = $? [JCI+) - (1-) Ephoton hf Hot Not = Putting J = 2 YZ2 I = 2h u2I 2* 6-626*104 473/1.63*10-45) =

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