0.150 mol of a solute is dissolved in 300. g of carbon tetrachloride. Calculate (a) the...

Question

Question

$0.150 mol of a solute is dissolved in 300. g of carbon tetrachloride. Calculate (a) the mole fraction and (b) the molality of$

Answer 1

Answer #1

(1000g = 1kg) moles of solute = 0.150 mol mas of coly (solvent) = 300g = 0.3 kg moler mass of CCl4 = 153.82 g/mol moles of cc

Answer 2

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