Question

Part A A circular loop of wire has radius of 5.50 cm A sinusoidal electromagnetic plane wave traveling in air passes through

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Answer #1

magnetic field corresponding to em wave

B^2 = 2 uo I / c

B^2 = 2* 4* 3.14* 10^-7* 0.0295 / (3* 10^8)

B = 1.572* 10^-8

angular frequency

w = 3* 10^8* 2 pi / 6.5

w = 2.898* 10^8 rad/s

now, net emf

e = A B w = pi r^2 B w

e = 3.14* 0.055^2* 1.572* 10^-8* 2.898* 10^8

e = 0.04328 V

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Comment before rate in case any doubt, will reply for sure.. goodluck

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