mixtureof HNO2 and NaNO2 act as acidic buffer
for such buffer
pH = pKa + log [NaNO2] / [HNO2]
pH = 3.26
[HNO2] = (21.52 / 47) (1/1) = 0.458 M
pKa = - log Ka = - log 4.0 x 10-4 = 3.40
[NaNO2] = ?
3.26 = 3.40 + log [NaNO2] / [0.458]
- 0.14 = log [NaNO2] + 0.34
- 0.48 = log [NaNO2]
[NaNO2] = 0.331 M
now
0.331 = (W / 69) (1 / 1)
W = 22.84 g
mass of NaNO2 required = 22.84 g
İl See Periodic Table O See Hint A 100 L solution contains 2132 of nitrous acid,...
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