Question

A dog running in an open field has components of velocity vx = 2.7 m/s and vy = -1.4 m/s at time t1 = 11.1 s . For the time interval from t1 = 11.1 s to t2 = 23.1 s , the average acceleration of the dog has magnitude 0.51 m/s2 and direction 31.0 ∘ measured from the +x−axis toward the +y−axis.

1) At time t2 = 23.1 s , what is the x-component of the dog's velocity?

2) At time t2 = 23.1 s , what is the y-component of the dog's velocity?

3) What is the magnitude of the dog's velocity?

4) What is the direction of the dog's velocity (measured from the +x−axis toward the +y−axis)?

Answer 1

(a) x-component is 7.98 m/s

(b) y-component is 1.84 m/s

(c) magnitude of dog's velocity is 8.2 m/s

(d) Direction is 12.95^{$\dpi{80} ^{\circ}$} with +x-axis