4 HCl (g) + O2 (g) -> 2 Cl (g) + 2 H2O (g) calculate the...

Question

Question

4 HCl (g) + O2 (g) -> 2 Cl (g) + 2 H2O (g)

calculate the number of grams of Cl2 formed when 0.385 mol HCl reacts with an excess of O2

Answer 1

Answer #1

From given balanced equation,

Mol of Cl2 formed = (2/4)*mol of HCl reacted

= (2/4)*0.385 mol

= 0.1925 mol

Molar mass of Cl2 = 70.9 g/mol

use:

mass of Cl2,

m = number of mol * molar mass

= 0.1925 mol * 70.9 g/mol

= 13.65 g

Answer: 13.6 g

Answer 2

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