Question

Seven balls numbered 1 to 7 are placed in a bag. Some of the balls are grey and some are white, as shown below. A ball will be selected from the bag at random. The 7 possible outcomes are listed in the table below. Note that each outcome has the same probability. Complete parts (a) through (c). Write the probabilities as fractions. (a) Check the outcomes for each event in the table. Then, in the last column, enter the probability of the event. Outcomes 5 6 7 Probability Event A: The selected ball has a number from 2 to5 Event B: The selected ball is grey Event A and B: The selected ball has a number from 2 to 5 and is grey Event A or B: The selected ball has a number from 2 to 5 or is grey (b) Compute the following. PA) + P(B) -P( and B)7 (c) Select the answer that makes the equation true. P (4) + P (B)-P (A and B) = (Choose one) ▼ Explanation Check
Help with c. Check a and b.

Answer 1

In c) part the given statement is

P(A) + P(B) - P( A and B) = P(A or B)

This is same as P( A or B), as we have added both probabilities for A and B, and by doing this the common probability is added twice so subtracted P(A and B) once to get P(A or B) .

I don't know what the options are there in drop down. It there are some other options please let me know I will answer accordingly.