Question

A person's body is producing energy internally due to metabolic processes. If the body loses more energy than metabolic processes are generating, its temperature will drop. If the drop is severe, it can be life-threatening. Suppose a person is unclothed and energy is being lost via radiation from a body surface area of 1.58 m2, which has a temperature of 34 °C and an emissivity of 0.626. Suppose that metabolic processes are producing energy at a rate of 174 J/s. What is the temperature in kelvins of the coldest room in which this person could stand and not experience a drop in body temperature?

Answer 1

T= 307k - using stefan's law of cooling • E = €0(T? To") . for the body temperature not to - drop, rate of loss of energy should be . equal to rate of production of energy which ir 1745/5 body Area A = 1.58 m² body temp. I= 34°C T=24+273) k - Emissinity E=0.626 . To = ? hence 174 = 0-62645-67X16* (3079-T;") >> (307)%-To" = 174 1-5840.62645.67 X 10R = 31.03 x108 T."= (307)"- 31.03 X 10% = 57.80 xide .:T. = (57.80 x 1080) = 2.757 X10*K = 275.7k To = 2,70]